将网络202.121.52.0/22划分为16个子网，下列网-名校题库网

将网络202.121.52.0/22划分为16个子网，下列网络地址不属于这16个子网的是(53)。

A.202.121.52.32/26
B.202.121.53.64/26
C.202.121.54.128/26
D.202.121.55.192/26

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答案： A

本题解析：

方法1：计算各个选项是否为网络地址，只有A不是网络地址，所以选A。方法2：选项中，掩码/26表示的的网络规模为2^(32-26)=2^6=64，所以用各选项的第四字节÷64，能整除就是网络地址，不能整除的A就是答案。方法3：划二进制为202.121.001101|00.00|000000，两个“|”之间就是可变部分，16个子网就是分别取0000、0001、0010、0011、...、1110、1111，既202.121.001101|00.01|000000、202.121.001101|00.01|000000、202.121.001101|00.10|000000、....，再把二进制划为10进制就等得到16个子网地址。

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